When the innerDiv is clicked, in what order will the event listeners be called according to the provided code?

In the context of event propagation in web development, specifically with regard to event bubbling, when an event occurs on an element, it first triggers the event listeners on that element, and then the event bubbles up to its parent elements, triggering their event listeners in the order they appear in the DOM hierarchy.

The specified answer indicates that when the inner div is clicked, the event listeners will call displayOuterMessage first, followed by displayInnerMessage. This suggests that the event listener for the parent element (outer div) executes before the listener for the child element (inner div).

This scenario aligns with the concept of event bubbling, which happens when an event is dispatched from a child element and then propagates upwards to its parent elements. Therefore, if there's a click listener attached to both the inner and outer div, the listener associated with the outer div is executed before the one on the inner div. Consequently, the order of execution would be displayOuterMessage followed by displayInnerMessage.

This phenomenon occurs because, in typical event scenarios, the event does not halt at the target element; it continues up the DOM tree unless stopped explicitly by methods like stopPropagation() or if the event